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(A) The amplification factor $\mu$ is defined as the ratio of the change in plate voltage to the change in grid voltage while keeping the plate curren

Vedclass · Accepted Answer

$10$

Vedclass · Answer

(A) The amplification factor $\mu$ is defined as the ratio of the change in plate voltage to the change in grid voltage while keeping the plate current constant.$\mu = - \left( \frac{\Delta V_p}{\Delta V_g} ight)_{i_p = 	ext{constant}}$From the graph,consider two curves representing constant plate currents. Let us take the curves corresponding to $V_p = 80 \ V$ and $V_p = 60 \ V$.For a constant plate current,the corresponding grid voltages are $V_g = -6 \ V$ and $V_g = -4 \ V$ respectively.$\Delta V_p = 80 \ V - 60 \ V = 20 \ V$$\Delta V_g = -6 \ V - (-4 \ V) = -2 \ V$$\mu = - \left( \frac{20 \ V}{-2 \ V} ight) = 10$Therefore,the correct option is $A$.

$V_g$ (volt)	$0$	$-2$	$-4$	$-6$
$I_p$ (mA) for $V_p = 150$ $V$	$15$	$12.5$	$10$	$7.5$
$I_p$ (mA) for $V_p = 120$ $V$	$10$	$7.5$	$5$	$2.5$

The value of the amplification factor from the following graph is:

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