The phase difference between two points separated by $0.8 \ m$ in a wave of frequency $120 \ Hz$ is $90^o$. Then the velocity of the wave will be ............ $m/s$.

The equation of a wave is $y = 2 \sin \pi (0.5x - 200t)$,where $x$ and $y$ are expressed in $cm$ and $t$ in $sec$. The wave velocity is ...... $cm/sec$.

$A$ transverse wave is represented by $y = A \sin(\omega t - kx)$. For what value of the wavelength is the wave velocity equal to the maximum particle velocity?

The distance between two consecutive points with a phase difference of $60^{\circ}$ in a wave of frequency $500 \text{ Hz}$ is $0.6 \text{ m}$. The velocity with which the wave is travelling is: (in $\text{ km/s}$)

The equation of a progressive wave is $y = 4 \sin(4 \pi t - 0.04 x + \pi / 3)$,where $x$ is in meters and $t$ is in seconds. The velocity of the wave is:

$A$ wave travelling along the $x$-axis is described by the equation $y(x, t) = 0.005 \cos(\alpha x - \beta t)$. If the wavelength and the time period of the wave are $0.08 \ m$ and $2.0 \ s$ respectively,then $\alpha$ and $\beta$ in appropriate units are: