The phase difference between input and output voltage of a $CE$ circuit is.....$^o$

$A$ transistor is connected in common emitter $(CE)$ configuration. The collector supply is $8\ V$ and the voltage drop across a resistor of $800\,\Omega$ in the collector circuit is $0.5\ V$. If the current gain factor $\alpha$ is $0.96$,find the base current in $\mu A$.

In the figure,given that $V_{BB}$ supply can vary from $0$ to $5.0 \,V$,$V_{CC} = 5\,V$,$\beta_{dc} = 200$,$R_B = 100\,k\Omega$,$R_C = 1\,k\Omega$ and $V_{BE} = 1.0\,V$. The minimum base current and the input voltage at which the transistor will go to saturation,will be respectively:

In common emitter mode of a transistor, the current gain is $8$. The input impedance is $25 \, k\Omega$ and load resistance is $75 \, k\Omega$. The power gain is

The voltage gain and current gain of a transistor amplifier in common emitter configuration are respectively $150$ and $50$. If the resistance in the base circuit is $850 \Omega$, then the resistance in the collector circuit is: (in $\Omega$)

In an amplifier circuit,the value of the load resistance $R_L$ is $2 \text{ k}\Omega$. $A$ change of $10 \text{ }\mu\text{A}$ in the base current of the transistor results in a change of $1 \text{ mA}$ in the collector current. The change in the collector-emitter voltage $(V_{CE})$ is ....... $V$.