The particular solution of $e^{\frac{y}{x}} = x, y(1) = 3, x > 0$ is . . . . . . .

  • A
    $\log y = x^2 + 4$
  • B
    $y = x \log x + 3x$
  • C
    $y^2 = \log x + 4$
  • D
    $2y = x^2 + 5$

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