The p.m.f of a random variable $X$ is given by $P(X) = \frac{2x}{n(n+1)}$ for $x = 1, 2, 3, \ldots, n$,and $0$ otherwise. Then $E(X) = $

  • A
    $\frac{n+1}{3}$
  • B
    $\frac{2n+1}{3}$
  • C
    $\frac{n+2}{3}$
  • D
    $\frac{2n-1}{3}$

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