The oxidation state of copper changes when aq | vedclass

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(C) Let us analyze the reactions of $Cu^{2+}_{(aq)}$ with the given reagents:$(I)$ Reaction with $NaOH_{(aq)}$: $Cu^{2+}_{(aq)} + 2OH^-_{(aq)} \righta

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$II, III$

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(C) Let us analyze the reactions of $Cu^{2+}_{(aq)}$ with the given reagents:$(I)$ Reaction with $NaOH_{(aq)}$: $Cu^{2+}_{(aq)} + 2OH^-_{(aq)} \rightarrow Cu(OH)_{2(s)}$. This is a precipitation reaction where the oxidation state of copper remains $+2$.$(II)$ Reaction with $Fe_{(s)}$: $Cu^{2+}_{(aq)} + Fe_{(s)} \rightarrow Cu_{(s)} + Fe^{2+}_{(aq)}$. This is a redox reaction where copper is reduced from $+2$ to $0$.$(III)$ Reaction with $KI_{(aq)}$: $2Cu^{2+}_{(aq)} + 4I^-_{(aq)} \rightarrow Cu_2I_{2(s)} + I_{2(s)}$. This is a redox reaction where copper is reduced from $+2$ to $+1$.Thus,the oxidation state of copper changes in reactions $(II)$ and $(III)$.

The oxidation state of copper changes when aqueous copper $(II)$ ions react with
$(I)$ $NaOH_{(aq)}$
$(II)$ $Fe_{(s)}$
$(III)$ $KI_{(aq)}$

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The oxidation state of copper changes when aqueous copper $(II)$ ions react with $(I)$ $NaOH_{(aq)}$ $(II)$ $Fe_{(s)}$ $(III)$ $KI_{(aq)}$