The oxidation state of manganese in the produ | vedclass

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Question

(C) In a basic medium,potassium permanganate $(KMnO_4)$ reacts with hydrogen peroxide $(H_2O_2)$ to produce manganese dioxide $(MnO_2)$,oxygen gas $(O

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(C) In a basic medium,potassium permanganate $(KMnO_4)$ reacts with hydrogen peroxide $(H_2O_2)$ to produce manganese dioxide $(MnO_2)$,oxygen gas $(O_2)$,water $(H_2O)$,and potassium hydroxide $(KOH)$.The balanced chemical equation is:$2KMnO_4 + 3H_2O_2 \longrightarrow 2MnO_2 + 3O_2 + 2H_2O + 2KOH$In the product $MnO_2$,let the oxidation state of $Mn$ be $x$.$x + 2(-2) = 0$$x - 4 = 0$$x = +4$Therefore,the oxidation state of manganese in the product is $4$.

The oxidation state of manganese in the product obtained in a reaction of potassium permanganate and hydrogen peroxide in basic medium is $.....$

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