The oxidation numbers of sulphur in S_8,S_2F_ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $1$. For $S_8$: Since it is an elemental form of sulphur,the oxidation number is $0$.$2$. For $S_2F_2$: Let the oxidation number of $S$ be $x$. Si

Vedclass · Accepted Answer

$0, +1, -2$

Vedclass · Answer

(A) $1$. For $S_8$: Since it is an elemental form of sulphur,the oxidation number is $0$.$2$. For $S_2F_2$: Let the oxidation number of $S$ be $x$. Since the oxidation number of $F$ is $-1$,we have $2x + 2(-1) = 0$,which gives $2x = 2$,so $x = +1$.$3$. For $H_2S$: Let the oxidation number of $S$ be $x$. Since the oxidation number of $H$ is $+1$,we have $2(+1) + x = 0$,which gives $x = -2$.Therefore,the oxidation numbers are $0, +1, -2$.

The oxidation numbers of sulphur in $S_8$,$S_2F_2$,and $H_2S$ respectively,are:

Similar Questions

If $M$ is the molecular weight of $KMnO_4$,what will be its equivalent weight when it is converted into $K_2MnO_4$?

What is the change in the oxidation state of nitrogen when $HNO_3$ is converted into $N_2O$?

$KMnO_4$ acts as an oxidising agent in the neutral medium and gets reduced to $MnO_2$. What is the equivalent weight of $KMnO_4$ in a neutral medium?

The oxidation number of carbon in $CH_2Cl_2$ is .........

What is the oxidation number of phosphorus in calcium phosphate?

Vedclass Test Series

Exam Paper Generator

Online Exam Module