The output of a step-down transformer is measured to be $48 \,V$ when connected to a $12 \,W$ bulb. The value of peak current is

  • A
    $1/\sqrt{2} \,A$
  • B
    $\sqrt{2} \,A$
  • C
    $1/(2\sqrt{2}) \,A$
  • D
    $1/4 \,A$

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