The osmotic pressure of a 5% , w/v solution o | vedclass

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(C) The concentration $C$ in $mol \ L^{-1}$ is calculated as: $C = \frac{5 \ g}{342 \ g/mol} 	imes \frac{1}{0.1 \ L} = \frac{50}{342} \ mol \ L^{-1}$

Vedclass · Accepted Answer

$5.08$

Vedclass · Answer

(C) The concentration $C$ in $mol \ L^{-1}$ is calculated as: $C = \frac{5 \ g}{342 \ g/mol} 	imes \frac{1}{0.1 \ L} = \frac{50}{342} \ mol \ L^{-1}$.Using the osmotic pressure formula $\pi = CRT$,where $R = 0.0821 \ L \ atm \ K^{-1} \ mol^{-1}$ and $T = 150 + 273 = 423 \ K$:$\pi = \frac{50}{342} 	imes 0.0821 	imes 423 \approx 5.08 \ atm$.

The osmotic pressure of a $5\% \, w/v$ solution of cane sugar at $150 \, ^\circ C$ is ......... $atm$.

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