The osmotic pressure of 2.22 % (w/v) CaCl_2 s | vedclass

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(D) Given: $w/v\ \% = 2.22\ \%$,which means $2.22\ g$ of $CaCl_2$ in $100\ mL$ of solution.$T = 27\ ^oC = 300\ K$.$w_B = 2.22\ g$,$v = 0.1\ L$.$M_B$ o

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$14.4\ atm$

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(D) Given: $w/v\ \% = 2.22\ \%$,which means $2.22\ g$ of $CaCl_2$ in $100\ mL$ of solution.$T = 27\ ^oC = 300\ K$.$w_B = 2.22\ g$,$v = 0.1\ L$.$M_B$ of $CaCl_2 = 40 + 2 	imes 35.5 = 111\ g/mol$.Number of moles $n = \frac{2.22}{111} = 0.02\ mol$.For $CaCl_2 ightarrow Ca^{2+} + 2Cl^-$,the van't Hoff factor $i = 3$.Osmotic pressure $\pi = i 	imes \frac{n}{v} 	imes R 	imes T$.$\pi = 3 	imes \frac{0.02}{0.1} 	imes 0.08 	imes 300$.$\pi = 3 	imes 0.2 	imes 0.08 	imes 300 = 14.4\ atm$.

The osmotic pressure of $2.22\ \%\ (w/v)$ $CaCl_2$ solution at $27\ ^oC$ is $(R = 0.08\ L\ atm\ K^{-1}\ mol^{-1})$

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