Solutions $A, B, C$ and $D$ are respectively $0.2 \ M$ urea,$0.10 \ M$ $NaCl$,$0.05 \ M$ $BaCl_{2}$ and $0.05 \ M$ $AlCl_{3}$. All solutions are isotonic with each other except:

  • A
    $B$
  • B
    $A$
  • C
    $D$
  • D
    $C$

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If a $5.25\% \, w/v$ solution of a substance is isotonic with a $1.5\% \, w/v$ solution of urea $(Molar \, mass = 60 \, g \, mol^{-1})$ in the same solvent,then the molar mass of the substance is ........ $g \, mol^{-1}$. (in $.0$)

$A$ $5.25\%$ solution of a substance is isotonic with a $1.5\%$ solution of urea (molar mass $= 60\ g\ mol^{-1}$) in the same solvent. If the densities of both the solutions are assumed to be equal to $1.0\ g\ cm^{-3},$ the molar mass of the substance will be .............. $g\ mol^{-1}$.

$A$ solution has an osmotic pressure of $x \ kPa$ at $300 \ K$ having $1 \ mole$ of solute in $10.5 \ m^{3}$ of solution. If its osmotic pressure is reduced to $(\frac{1}{10})$th of its initial value,what is the new volume of solution (in $m^{3}$)?

$A$ solution containing $4 \ g$ of polymer in $4.0 \ L$ solution at $27^{\circ} C$ shows an osmotic pressure of $3.0 \times 10^{-4} \ atm$. The molar mass of the polymer in $g \ mol^{-1}$ is

$0.06 \% (w/v)$ aqueous solution of urea is isotonic with:

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