The order of the differential equation,whose | vedclass

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(B) Given the solution: $y=(C_1+C_2) e^x+C_3 e^{x+C_4}$ We can simplify the expression as follows: $y = (C_1+C_2) e^x + C_3 e^x \cdot e^{C_4}$ Let $A

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$1$

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(B) Given the solution: $y=(C_1+C_2) e^x+C_3 e^{x+C_4}$ We can simplify the expression as follows: $y = (C_1+C_2) e^x + C_3 e^x \cdot e^{C_4}$ Let $A = C_1+C_2$ and $B = C_3 e^{C_4}$. Then the equation becomes $y = Ae^x + Be^x = (A+B) e^x$. Let $D = A+B$,where $D$ is a single arbitrary constant. Thus,the equation simplifies to $y = De^x$. Since the final form of the solution contains only one arbitrary constant,the order of the corresponding differential equation is $1$.

The order of the differential equation,whose solution is $y=(C_1+C_2) e^x+C_3 e^{x+C_4}$,is

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