The octant in which the point (2, -4, -7) lie | vedclass

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Question

(A) The signs of the coordinates $(x, y, z)$ in the eight octants are given in the table below:| Octant | $I$ | $II$ | $III$ | $IV$ | $V$ | $VI$ | $VI

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Eighth

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(A) The signs of the coordinates $(x, y, z)$ in the eight octants are given in the table below:| Octant | $I$ | $II$ | $III$ | $IV$ | $V$ | $VI$ | $VII$ | $VIII$ || :--- | :--- | :--- | :--- | :--- | :--- | :--- | :--- | :--- || $x$ | $+$ | $-$ | $-$ | $+$ | $+$ | $-$ | $-$ | $+$ || $y$ | $+$ | $+$ | $-$ | $-$ | $+$ | $+$ | $-$ | $-$ || $z$ | $+$ | $+$ | $+$ | $+$ | $-$ | $-$ | $-$ | $-$ |Given the point $(2, -4, -7)$,we have:$x = 2$ (positive,$+$)$y = -4$ (negative,$-$)$z = -7$ (negative,$-$)Looking at the table,the octant where $x$ is positive,$y$ is negative,and $z$ is negative is the $VIII$ octant.

The octant in which the point $(2, -4, -7)$ lies is

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