The number of ways in which $3$ children can distribute $10$ tickets out of $15$ consecutively numbered tickets themselves such that they get consecutive blocks of $5, 3$ and $2$ tickets is

  • A

    $^8{C_5}$

  • B

    $^8{C_5} 3!$

  • C

    $^8{C_5} (3!)^2$

  • D

    none of these

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