(A) The electronic configuration of uranium $({ }_{92} U)$ is $[Rn] \ 5f^{3} \ 6d^{1} \ 7s^{2}$.In the $5f$ subshell,there are $3$ unpaired electrons,

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(A) The electronic configuration of uranium $({ }_{92} U)$ is $[Rn] \ 5f^{3} \ 6d^{1} \ 7s^{2}$.In the $5f$ subshell,there are $3$ unpaired electrons,and in the $6d$ subshell,there is $1$ unpaired electron.The $7s$ subshell is fully filled.Therefore,the total number of unpaired electrons is $3 + 1 = 4$.