Most common oxidation states of Ce are | vedclass

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Question

(C) Cerium ($Ce$,atomic number $58$) is a lanthanoid element. Its electronic configuration is $[Xe] 4f^1 5d^1 6s^2$. It commonly exhibits $+3$ oxidati

Vedclass · Accepted Answer

$+3, +4$

Vedclass · Answer

(C) Cerium ($Ce$,atomic number $58$) is a lanthanoid element. Its electronic configuration is $[Xe] 4f^1 5d^1 6s^2$. It commonly exhibits $+3$ oxidation state,which is the characteristic oxidation state of lanthanoids. It also exhibits $+4$ oxidation state because,in the $+4$ state,it achieves a stable noble gas configuration $([Xe])$. Therefore,the most common oxidation states of $Ce$ are $+3$ and $+4$.

Most common oxidation states of $Ce$ are

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