The number of stereoisomers possible for the | vedclass

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Question

(c) Total number of possible stereoisomers in an unsymmetrical compound $=$ Number of optical isomers $+$ Number of geometrical isomers.
In given com

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(c) Total number of possible stereoisomers in an unsymmetrical compound $=$ Number of optical isomers $+$ Number of geometrical isomers.
In given compound, there is one chiral carbon.
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$n=1$
$	herefore$ Number of optical isomers $=2$
Also, the compound contains a double bond, thus it will have two geometrical isomers also (cis and trans form).
Thus, total number of stereoisomers $=2+2=4$.

The number of stereoisomers possible for the following compound is
$CH _{3}- CH = CH - CH ( Br )- CH _{2}- CH _{3}$

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The number of stereoisomers possible for the following compound is $CH _{3}- CH = CH - CH ( Br )- CH _{2}- CH _{3}$