Which of the following compounds has a plane | vedclass

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(D) plane of symmetry $(POS)$ is an imaginary plane that bisects a molecule into two halves that are mirror images of each other. $1.$ In $R-R$ $(CH_3

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(D) plane of symmetry $(POS)$ is an imaginary plane that bisects a molecule into two halves that are mirror images of each other. $1.$ In $R-R$ $(CH_3-CH(Cl)-CH(Cl)-CH_3)$ and $S-S$ $(Br-CH(Cl)-CH(Cl)-Br)$,these molecules can exist as meso forms (which have a $POS$) or as enantiomeric pairs (which do not). However,the structures provided represent specific chiral configurations that do not possess a plane of symmetry. $2.$ In $R-S$ $(CH_3-CH(Cl)-CH(Cl)-Br)$,the two ends of the molecule are different ($CH_3$ and $Br$). Therefore,no plane can divide the molecule into two identical mirror-image halves,regardless of the configurations of the chiral centers. Since none of the given specific configurations possess a plane of symmetry,the correct answer is $(d)$.

Which of the following compounds has a plane of symmetry?
$R = -CH(Cl)-CH_3$
$S = -CH(Cl)-Br$

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Which of the following compounds has a plane of symmetry? $R = -CH(Cl)-CH_3$ $S = -CH(Cl)-Br$