The number of significant figures in the simplification of $\frac{0.501}{0.05}(0.312-0.03)$ is

  • A
    $1$
  • B
    $3$
  • C
    $2$
  • D
    $5$

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For the four sets of three measured physical quantities as given below,which of the following options is correct?
$(i)$ $A_{1}=24.36, B_{1}=0.0724, C_{1}=256.2$
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