In an experiment on a simple pendulum to dete | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The length of the pendulum $(L)$ is given by the sum of the length of the thread $(l)$ and the radius of the bob $(r)$.$L = l + r$Given,$l = 63.2

Vedclass · Accepted Answer

$64.3$

Vedclass · Answer

(B) The length of the pendulum $(L)$ is given by the sum of the length of the thread $(l)$ and the radius of the bob $(r)$.$L = l + r$Given,$l = 63.2 \,cm$ and diameter $d = 2.256 \,cm$.Radius $r = \frac{d}{2} = \frac{2.256}{2} = 1.128 \,cm$.$L = 63.2 + 1.128 = 64.328 \,cm$.According to the rules of significant figures in addition/subtraction,the result should be reported to the same number of decimal places as the measurement with the fewest decimal places.Here,$63.2$ has one decimal place and $1.128$ has three decimal places.Therefore,the result must be rounded to one decimal place.$L = 64.3 \,cm$.

In an experiment on a simple pendulum to determine the acceleration due to gravity,a student measures the length of the thread as $63.2 \,cm$ and the diameter of the pendulum bob as $2.256 \,cm$. The student should take the length of the pendulum to be ........... $cm$.

Similar Questions

The number of significant figures in $200.40$ is

Calculate the length of the arc of a circle of radius $31.0 \, cm$ which subtends an angle of $\frac{\pi}{6}$ at the centre.

$A$ person measures the mass of $3$ different particles as $435.42 \ g$,$226.3 \ g$,and $0.125 \ g$. According to the rules for arithmetic operations with significant figures,the sum of the masses of the $3$ particles will be: (in $g$)

The number of significant figures in the measured value $4.700 \,m$ is the same as that in the value ....... $m$

The respective number of significant figures for the numbers $23.023$,$0.0003$,and $2.1 \times 10^3$ are:

Vedclass Test Series

Exam Paper Generator

Online Exam Module