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(A) The reaction of $3$-chloro-$1$-butene with $HCl$ proceeds via the formation of a carbocation intermediate.First,the $H^+$ ion from $HCl$ adds to t

Vedclass · Accepted Answer

$4$

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(A) The reaction of $3$-chloro-$1$-butene with $HCl$ proceeds via the formation of a carbocation intermediate.First,the $H^+$ ion from $HCl$ adds to the double bond to form a carbocation.This carbocation can undergo a $1,2$-hydride shift to form a more stable carbocation.$1$. The initial carbocation reacts with $Cl^-$ to form $2,3$-dichlorobutane. This product has two chiral centers,leading to $3$ stereoisomers ($d, l$ and $meso$ forms).$2$. The rearranged carbocation reacts with $Cl^-$ to form $2,2$-dichlorobutane,which is an achiral product ($1$ isomer).Total number of possible isomeric products $= 3 + 1 = 4$.

The number of possible isomeric products formed when $3$-chloro-$1$-butene reacts with $HCl$ through carbocation formation is $.............$.

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