The number of moles of AgCl precipitate forme | vedclass

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(B) The given coordination compound is $[Cr(NH_3)_4Cl_2]Cl$.In this complex,there is only $1$ chloride ion outside the coordination sphere,which acts

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$1$

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(B) The given coordination compound is $[Cr(NH_3)_4Cl_2]Cl$.In this complex,there is only $1$ chloride ion outside the coordination sphere,which acts as an ionizable group.When excess $AgNO_3$ is added,the ionizable $Cl^-$ reacts with $Ag^+$ to form $AgCl$ precipitate according to the reaction: $[Cr(NH_3)_4Cl_2]Cl + AgNO_3 \rightarrow [Cr(NH_3)_4Cl_2]NO_3 + AgCl \downarrow$.Since there is $1$ mole of ionizable $Cl^-$ per mole of the complex,$1$ mole of $AgCl$ precipitate is formed.

The number of moles of $AgCl$ precipitate formed when an excess of $AgNO_3$ is added to one mole of $[Cr(NH_3)_4Cl_2]Cl$ is:

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