In the complex ion [Cr(H_2O)_6]^{3+},the coor | vedclass

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(C) The coordination number of a central metal ion is defined as the number of ligand donor atoms to which the metal is directly bonded.In the complex

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$6$

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(C) The coordination number of a central metal ion is defined as the number of ligand donor atoms to which the metal is directly bonded.In the complex $[Cr(H_2O)_6]^{3+}$,the central metal ion is $Cr^{3+}$.It is bonded to $6$ water $(H_2O)$ molecules.Since $H_2O$ is a monodentate ligand,each molecule donates one pair of electrons to the central metal.Therefore,the coordination number of $Cr$ is $6 	imes 1 = 6$.

In the complex ion $[Cr(H_2O)_6]^{3+}$,the coordination number of $Cr$ is:

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