The number of molecules present in 1 cm^{3} | vedclass

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Question

(B) Density of water $= 1 \ g/mL = 1 \ g/cm^{3}$.Mass of $1 \ cm^{3}$ of water $=$ density $	imes$ volume $= 1 \ g/cm^{3} 	imes 1 \ cm^{3} = 1 \ g$.

Vedclass · Accepted Answer

$3.3 	imes 10^{22}$

Vedclass · Answer

(B) Density of water $= 1 \ g/mL = 1 \ g/cm^{3}$.Mass of $1 \ cm^{3}$ of water $=$ density $	imes$ volume $= 1 \ g/cm^{3} 	imes 1 \ cm^{3} = 1 \ g$.Molar mass of water $(H_{2}O)$ $= (2 	imes 1) + 16 = 18 \ g/mol$.Number of moles of water $= \frac{	ext{mass}}{	ext{molar mass}} = \frac{1}{18} \ mol$.Number of molecules $= 	ext{moles} 	imes N_{A} = \frac{1}{18} 	imes 6.022 	imes 10^{23} \approx 3.34 	imes 10^{22}$ molecules.

The number of molecules present in $1 \ cm^{3}$ of water is

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