Volume occupied by one molecule of water (den | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The molar mass of water $(H_2O)$ is $18.02 \ g \ mol^{-1}$.Given density of water is $1 \ g \ cm^{-3}$.Volume of $1 \ mol$ of water $= 	ext{Mass}

Vedclass · Accepted Answer

$3.0$

Vedclass · Answer

(A) The molar mass of water $(H_2O)$ is $18.02 \ g \ mol^{-1}$.Given density of water is $1 \ g \ cm^{-3}$.Volume of $1 \ mol$ of water $= 	ext{Mass} / 	ext{Density} = 18.02 \ g / 1 \ g \ cm^{-3} = 18.02 \ cm^3$.Since $1 \ mol$ contains $6.022 	imes 10^{23}$ molecules,the volume occupied by one molecule is:$V = 18.02 \ cm^3 / 6.022 	imes 10^{23} 	ext{ molecules} \approx 2.99 	imes 10^{-23} \ cm^3 \approx 3.0 	imes 10^{-23} \ cm^3$.

Volume occupied by one molecule of water (density $= 1 \ g \ cm^{-3}$) is ...... $ \times 10^{-23} \ cm^3$.

Similar Questions

Calculate the mass of oxygen present in $0.1 \ mol$ of $Na_2CO_3 \cdot 10H_2O$. (in $g$)

What is the number of moles of sulfur atoms present in $n$ mole molecules of mustard gas?

Explain the mole concept.

Find the number of electrons present in $34 \ g$ of $NH_{3(g)}$. (Express your answer in terms of $N_A$)

The number of hydrogen atoms in $0.9 \ g$ glucose $(C_6H_{12}O_6)$ $(M_w = 180 \ g/mol)$ is same as

Vedclass Test Series

Exam Paper Generator

Online Exam Module