The number of molecules of $CO_2$ liberated by the complete combustion of $0.1 \text{ mol}$ of graphite in air is:

  • A
    $3.01 \times 10^{22}$
  • B
    $6.02 \times 10^{23}$
  • C
    $6.02 \times 10^{22}$
  • D
    $3.01 \times 10^{23}$

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