The apparent frequency of a sound wave as hea | vedclass

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(C) The apparent frequency is given by $f_{app} = f(1 + 0.1) = 1.1f$.The Doppler effect formula is $f_{app} = f \left[ \frac{v + v_o}{v - v_s} \right]

Vedclass · Accepted Answer

$i, iv$

Vedclass · Answer

(C) The apparent frequency is given by $f_{app} = f(1 + 0.1) = 1.1f$.The Doppler effect formula is $f_{app} = f \left[ \frac{v + v_o}{v - v_s} ight]$.Thus,$\frac{v + v_o}{v - v_s} = 1.1$.Case $1$: If the observer is stationary $(v_o = 0)$,then $\frac{v}{v - v_s} = 1.1$.$v = 1.1v - 1.1v_s \implies 1.1v_s = 0.1v \implies v_s = \frac{0.1 	imes 330}{1.1} = 30 \, m/s$.This matches statement $(i)$.Case $2$: If the source is stationary $(v_s = 0)$,then $\frac{v + v_o}{v} = 1.1$.$v + v_o = 1.1v \implies v_o = 0.1v = 0.1 	imes 330 = 33 \, m/s$.This matches statement $(iv)$.Therefore,the correct statements are $(i)$ and $(iv)$.

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