The number of lone pairs of electrons present on $Xe$ in $XeF_4$ is
- A$3$
- B$4$
- C$1$
- D$2$
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Similar Questions
Match List-$I$ with List-$II$.
List-$I$ List-$II$ $(a)$ $PCl_{5}$ $(i)$ Square pyramidal $(b)$ $SF_{6}$ $(ii)$ Trigonal planar $(c)$ $BrF_{5}$ $(iii)$ Octahedral $(d)$ $BF_{3}$ $(iv)$ Trigonal bipyramidal
Choose the correct answer from the options given below.
| List-$I$ | List-$II$ |
| $(a)$ $PCl_{5}$ | $(i)$ Square pyramidal |
| $(b)$ $SF_{6}$ | $(ii)$ Trigonal planar |
| $(c)$ $BrF_{5}$ | $(iii)$ Octahedral |
| $(d)$ $BF_{3}$ | $(iv)$ Trigonal bipyramidal |
Choose the correct answer from the options given below.
Match the following:
List-$I$ List-$II$ $a$. See-Saw Shape $i$. $XeF_4$ $b$. Square Pyramidal $ii$. $ClF_3$ $c$. $T$-Shape $iii$. $PbCl_2$ $d$. Bent Shape $iv$. $SF_4$ $v$. $BrF_5$
The correct answer is
| List-$I$ | List-$II$ |
| $a$. See-Saw Shape | $i$. $XeF_4$ |
| $b$. Square Pyramidal | $ii$. $ClF_3$ |
| $c$. $T$-Shape | $iii$. $PbCl_2$ |
| $d$. Bent Shape | $iv$. $SF_4$ |
| $v$. $BrF_5$ |
The correct answer is
The correct order of increasing bond angles is
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View SolutionThe geometry with respect to the central atom of the following molecules are: $N(SiH_3)_3;\, Me_3N;\, (SiH_3)_3P$
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