Match the following:List-IList-IIa. See-Saw S | vedclass

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(B) To determine the geometry,we use $VSEPR$ theory:$a$. $SF_4$: Steric number is $5$ ($4$ bond pairs + $1$ lone pair),resulting in a See-Saw shape $(

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$a-iv, b-v, c-ii, d-iii$

Vedclass · Answer

(B) To determine the geometry,we use $VSEPR$ theory:$a$. $SF_4$: Steric number is $5$ ($4$ bond pairs + $1$ lone pair),resulting in a See-Saw shape $(iv)$.$b$. $BrF_5$: Steric number is $6$ ($5$ bond pairs + $1$ lone pair),resulting in a Square Pyramidal shape $(v)$.$c$. $ClF_3$: Steric number is $5$ ($3$ bond pairs + $2$ lone pairs),resulting in a $T$-shape $(ii)$.$d$. $PbCl_2$: This is an ionic compound with a bent geometry in the gas phase due to the lone pair on $Pb^{2+}$ $(iii)$.Therefore,the correct matching is $a-iv, b-v, c-ii, d-iii$.

List-$I$	List-$II$
$a$. See-Saw Shape	$i$. $XeF_4$
$b$. Square Pyramidal	$ii$. $ClF_3$
$c$. $T$-Shape	$iii$. $PbCl_2$
$d$. Bent Shape	$iv$. $SF_4$
	$v$. $BrF_5$

Match the following:
List-$I$ List-$II$
$a$. See-Saw Shape $i$. $XeF_4$
$b$. Square Pyramidal $ii$. $ClF_3$
$c$. $T$-Shape $iii$. $PbCl_2$
$d$. Bent Shape $iv$. $SF_4$
$v$. $BrF_5$

The correct answer is

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Match the following:List-$I$List-$II$$a$. See-Saw Shape$i$. $XeF_4$$b$. Square Pyramidal$ii$. $ClF_3$$c$. $T$-Shape$iii$. $PbCl_2$$d$. Bent Shape$iv$. $SF_4$$v$. $BrF_5$The correct answer is