The number of incorrect statement/s from the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) . For a zero-order reaction,$t_{1/2} = \frac{[A]_0}{2K}$. As the concentration decreases,the half-life decreases. (Correct statement)$B$. If the o

Vedclass · Accepted Answer

$1$

Vedclass · Answer

(C) . For a zero-order reaction,$t_{1/2} = \frac{[A]_0}{2K}$. As the concentration decreases,the half-life decreases. (Correct statement)$B$. If the order with respect to a reactant is zero,it will not affect the rate of reaction. (Correct statement)$C$. Order can be fractional,but molecularity is always a whole number and cannot be fractional. (Incorrect statement)$D$. For a zero-order reaction,the unit is $mol \ L^{-1} s^{-1}$,and for a second-order reaction,the unit is $mol^{-1} L s^{-1}$. (Correct statement)Thus,only statement $C$ is incorrect. The number of incorrect statements is $1$.

Similar Questions

The rate law equation for a reaction between $A$,$B$ and $C$ is $r = k[A][B][C]^2$. What will be the new rate of reaction if the concentration of both $A$ and $B$ are doubled (in $r$)?

For the reaction $RCl + NaOH_{(aq)} \rightarrow ROH + NaCl$,the rate is given by $Rate = K_1[RCl]$. What will happen to the reaction rate?

For the hypothetical reaction $2X + G \to Q + 2M$,the rate expression is $\frac{d[Q]}{dt} = k[X]^2$. Which of the following is the most likely mechanism?

The rate of a reaction is given by $r = K[x][y] / [OH^-]$. If the concentration of $[OH^-]$ is increased,the order of the reaction will be ........

Which one of the following statements is correct for the reaction?
$CH_3COOC_2H_5(aq) + NaOH(aq) \longrightarrow CH_3COONa(aq) + C_2H_5OH(aq)$

Vedclass Test Series

Exam Paper Generator

Online Exam Module