(A) The structure of Hepta$-1, 3-$dien$-5-$yne is: $CH_2=CH-CH=CH-C\equiv C-CH_3$. Counting the hybridization of each carbon atom: $C_1$: $sp^2$ (one

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(A) The structure of Hepta$-1, 3-$dien$-5-$yne is: $CH_2=CH-CH=CH-C\equiv C-CH_3$. Counting the hybridization of each carbon atom: $C_1$: $sp^2$ (one double bond) $C_2$: $sp^2$ (one double bond) $C_3$: $sp^2$ (one double bond) $C_4$: $sp^2$ (one double bond) $C_5$: $sp$ (one triple bond) $C_6$: $sp$ (one triple bond) $C_7$: $sp^3$ (all single bonds) Thus,there are $2$ $sp$ hybridized carbons $(C_5, C_6)$ and $4$ $sp^2$ hybridized carbons $(C_1, C_2, C_3, C_4)$.

Class 11 Chemistry 8-1.Organic Chemistry : Classification and Nomenclature of Organic compounds Bonding and hybridisation in organic compounds

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The number of $sp$ and $sp^2$ hybridized carbon atoms in Hepta$-1, 3-$dien$-5-$yne,respectively,are

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$2, 4$
B
$4, 3$
C
$2, 2$
D
$2, 5$

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8-1.Organic Chemistry : Classification and Nomenclature of Organic compounds

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Bonding and hybridisation in organic compounds

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