The negation of the statement "If 5

Question

(A) Let $p: 5  2$,and $r: 5 > 2$. The given statement is of the form $(p \wedge q) \rightarrow r$. The negation of an implication $A \righ

Vedclass · Accepted Answer

$5  2$ and $5 \leq 2$

Vedclass · Answer

(A) Let $p: 5  2$,and $r: 5 > 2$. The given statement is of the form $(p \wedge q) ightarrow r$. The negation of an implication $A ightarrow B$ is $A \wedge \sim B$. Here,$A = (p \wedge q)$ and $B = r$. So,the negation is $(p \wedge q) \wedge \sim r$. Substituting the values: $(5  2) \wedge \sim(5 > 2)$. Since the negation of $5 > 2$ is $5 \leq 2$,the final statement is $(5  2) 	ext{ and } 5 \leq 2$.

The negation of the statement "If $5 < 7$ and $7 > 2$,then $5 > 2$" is

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