The inverse of the proposition (p wedge sim q | vedclass

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Question

(B) The inverse of a conditional statement $P \Rightarrow Q$ is defined as $\sim P \Rightarrow \sim Q$. Given the proposition $(p \wedge \sim q) \Righ

Vedclass · Accepted Answer

$\sim p \vee q \Rightarrow \sim r$

Vedclass · Answer

(B) The inverse of a conditional statement $P \Rightarrow Q$ is defined as $\sim P \Rightarrow \sim Q$. Given the proposition $(p \wedge \sim q) \Rightarrow r$,we identify $P = (p \wedge \sim q)$ and $Q = r$. Therefore,the inverse is $\sim(p \wedge \sim q) \Rightarrow \sim r$. Using De Morgan's Law,$\sim(p \wedge \sim q)$ is equivalent to $(\sim p \vee \sim(\sim q))$,which simplifies to $(\sim p \vee q)$. Thus,the inverse is $(\sim p \vee q) \Rightarrow \sim r$.

The inverse of the proposition $(p \wedge \sim q) \Rightarrow r$ is

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