The mutual inductance between the rectangular loop and the long straight wire as shown in figure is $M$.
$M =$ Zero
$M = \frac{{{\mu _0}a}}{{2\pi }}\ln \left( {1 + \frac{c}{b}} \right)$
$M =\frac{{{\mu _0}b}}{{2\pi }}\ln \left( {\frac{{a + c}}{b}} \right)$
$M =\frac{{{\mu _0}a}}{{2\pi }}\ln \left( {1 + \frac{b}{c}} \right)$
Find the mutual inductance in the arrangement, when a small circular loop of wire of radius ' $R$ ' is placed inside a large square loop of wire of side $L$ $( L \gg R )$. The loops are coplanar and their centres coincide :
Explain mutual induction and derive equation of mutual $\mathrm{emf}$.
A small circular loop of wire of radius $a$ is located at the centre of a much larger circular wire loop of radius $b$. The two loops are in the same plane. The outer loop of radius $b$ carries an alternating current $I = I_0\, cos\, (\omega t)$ . The emf induced in the smaller inner loop is nearly
Two coil $A$ and $B$ have coefficient of mutual inductance $M = 2H$. The magnetic flux passing through coil $A$ changes by $4$ Weber in $10$ seconds due to the change in current in $B$. Then
Two coaxial solenoids are made by winding thin insulated wire over a pipe of cross-sectional area $A = 10\ cm^2$ and length$= 20\ cm$. If one of the solenoid has $300$ turns and the other $400$ turns, their mutual inductance is
$\mu_{0}=4 \pi \times 10^{-7} \;TmA ^{-1}$