The most general value of theta satisfying t | vedclass

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(c) $	an 	heta = - 1 = 	an \left( {2\pi - \frac{\pi }{4}} ight) ,$

$\cos 	heta = \frac{1}{{\sqrt 2 }} = \cos \left( {2\pi - \frac{\pi }{4}} \

Vedclass · Accepted Answer

$2n\pi + \frac{{7\pi }}{4}$

Vedclass · Answer

(c) $	an 	heta = - 1 = 	an \left( {2\pi - \frac{\pi }{4}} ight) ,$

$\cos 	heta = \frac{1}{{\sqrt 2 }} = \cos \left( {2\pi - \frac{\pi }{4}} ight)$

Hence general value is $2n\pi + \left( {2\pi - \frac{\pi }{4}} ight) = 2n\pi + \frac{{7\pi }}{4}$.

The most general value of $\theta $ satisfying the equations $\tan \theta = - 1$ and $\cos \theta = \frac{1}{{\sqrt 2 }}$ is

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