The molecule having one unpaired electron is

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Question

(A) According to Molecular Orbital Theory $(MOT)$:$NO$ has a total of $15$ electrons ($7$ from $N$ and $8$ from $O$).The electronic configuration is:

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$NO$

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(A) According to Molecular Orbital Theory $(MOT)$:$NO$ has a total of $15$ electrons ($7$ from $N$ and $8$ from $O$).The electronic configuration is: $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2 = \pi 2p_y^2, \pi^* 2p_x^1$.Since there is one electron in the antibonding $\pi^* 2p_x$ orbital,$NO$ is paramagnetic and contains one unpaired electron.$CO$ ($14$ electrons) and $CN^{-}$ ($14$ electrons) are diamagnetic (zero unpaired electrons).$O_2$ ($16$ electrons) has two unpaired electrons in the $\pi^* 2p$ orbitals.

List-$I$	List-$II$
$(1)$ ${\rm{NO}}$	$(A)$ $1.5$
$(2)$ ${\rm{CO}}$	$(B)$ $2.0$
$(3)$ ${\rm{O}}_2^-$	$(C)$ $2.5$
$(4)$ ${\rm{O}}_2$	$(D)$ $3.0$

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Match the species given in List-$I$ with their bond orders given in List-$II$.

List-$I$ List-$II$

$(1)$ ${\rm{NO}}$ $(A)$ $1.5$

$(2)$ ${\rm{CO}}$ $(B)$ $2.0$

$(3)$ ${\rm{O}}_2^-$ $(C)$ $2.5$

$(4)$ ${\rm{O}}_2$ $(D)$ $3.0$

According to the Molecular Orbital Theory,which of the following does not exist?

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