(B) The electronic configuration of $B_{2}$ molecule ($10$ electrons) is: $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \pi 2p_x^1, \pi 2p_

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(B) The electronic configuration of $B_{2}$ molecule ($10$ electrons) is: $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \pi 2p_x^1, \pi 2p_y^1$. Number of bonding electrons $(N_b)$ = $2+2+1+1 = 6$. Number of antibonding electrons $(N_a)$ = $2+2 = 4$. Bond order = $\frac{N_b - N_a}{2} = \frac{6 - 4}{2} = \frac{2}{2} = 1$.