The mode of hybridisation of carbon in CO_2 i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The structure of $CO_2$ is $O=C=O$. In this molecule,the carbon atom forms two double bonds with two oxygen atoms. According to the steric number

Vedclass · Accepted Answer

$sp$

Vedclass · Answer

(A) The structure of $CO_2$ is $O=C=O$. In this molecule,the carbon atom forms two double bonds with two oxygen atoms. According to the steric number rule,the steric number is calculated as the number of sigma bonds plus the number of lone pairs on the central atom. For carbon in $CO_2$,there are $2$ sigma bonds and $0$ lone pairs,resulting in a steric number of $2$. $A$ steric number of $2$ corresponds to $sp$ hybridization.

The mode of hybridisation of carbon in $CO_2$ is

Similar Questions

In which one of the following pairs do the central atoms exhibit $sp^2$ hybridization?

When the hybridisation state of a carbon atom changes from $sp^3$ to $sp^2$ to $sp$,the angle between the hybridised orbitals

In ethene,the bond angle$(s)$ is/are

Sulphur trioxide is dissolved in heavy water to form a compound $X$. The hybridisation state of sulphur in $X$ is :

The trigonal bipyramidal geometry results from the hybridization:

Vedclass Test Series

Exam Paper Generator

Online Exam Module