Sulphur trioxide is dissolved in heavy water | vedclass

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(B) When $SO_3$ is dissolved in heavy water $(D_2O)$,it forms deuterated sulphuric acid $(D_2SO_4)$ as the compound $X$.The chemical reaction is: $SO_

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$sp^3$

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(B) When $SO_3$ is dissolved in heavy water $(D_2O)$,it forms deuterated sulphuric acid $(D_2SO_4)$ as the compound $X$.The chemical reaction is: $SO_3 + D_2O \longrightarrow D_2SO_4$ $(X)$.In $D_2SO_4$,the central sulphur atom is bonded to two $OD$ groups and two oxygen atoms via double bonds.The steric number of sulphur is calculated as: $	ext{Number of sigma bonds} + 	ext{Number of lone pairs} = 4 + 0 = 4$.$A$ steric number of $4$ corresponds to $sp^3$ hybridisation.

Sulphur trioxide is dissolved in heavy water to form a compound $X$. The hybridisation state of sulphur in $X$ is :

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