The median class of the following frequency d | vedclass

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(B) To find the median class,we first calculate the cumulative frequency $(cf)$ for each class:$1$. For class $0-10$,$cf = 4$.$2$. For class $10-20$,$

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$30-40$

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(B) To find the median class,we first calculate the cumulative frequency $(cf)$ for each class:$1$. For class $0-10$,$cf = 4$.$2$. For class $10-20$,$cf = 4 + 5 = 9$.$3$. For class $20-30$,$cf = 9 + 9 = 18$.$4$. For class $30-40$,$cf = 18 + 10 = 28$.$5$. For class $40-50$,$cf = 28 + 14 = 42$.$6$. For class $50-60$,$cf = 42 + 8 = 50$.The total number of observations is $n = 50$.We need to find the class where the cumulative frequency is greater than or equal to $\frac{n}{2} = \frac{50}{2} = 25$.Looking at the cumulative frequencies: $4, 9, 18, 28, 42, 50$.The first cumulative frequency greater than $25$ is $28$,which corresponds to the class interval $30-40$.Therefore,the median class is $30-40$.

Number of seats	$100-104$	$104-108$	$108-112$	$112-116$	$116-120$
Frequency	$15$	$20$	$32$	$18$	$15$

Class	$12.5-17.5$	$17.5-22.5$	$22.5-27.5$	$27.5-32.5$	$32.5-37.5$
Frequency	$2$	$22$	$19$	$14$	$13$

The median class of the following frequency distribution is ...........
Class $0-10$ $10-20$ $20-30$ $30-40$ $40-50$ $50-60$
Frequency $4$ $5$ $9$ $10$ $14$ $8$

Total frequency $n = 50$.

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Class	$0-10$	$10-20$	$20-30$	$30-40$	$40-50$	$50-60$
Frequency	$4$	$5$	$9$	$10$	$14$	$8$

The median class of the following frequency distribution is ...........Class$0-10$$10-20$$20-30$$30-40$$40-50$$50-60$Frequency$4$$5$$9$$10$$14$$8$Total frequency $n = 50$.