$Z - \bar{x} = \dots \times (M - \bar{x})$
- A$2$
- B$3$
- C$4$
- D$5$
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Similar Questions
In the formula $M = l + \frac{(\frac{n}{2} - cf)}{f} \times h$ for the median,$n = \ldots \ldots \ldots$
Easy
View SolutionIf $Z = 36.8$ and $M = 33.6$,then $\bar{x} = \ldots \ldots \ldots \ldots .$
Medium
View SolutionThe weights (in $kg$) of $50$ wrestlers are recorded in the following table:
Weight (in $kg$) $100-110$ $110-120$ $120-130$ $130-140$ $140-150$ Number of wrestlers $4$ $14$ $21$ $8$ $3$
Find the mean weight of the wrestlers (in $kg$).
| Weight (in $kg$) | $100-110$ | $110-120$ | $120-130$ | $130-140$ | $140-150$ |
| Number of wrestlers | $4$ | $14$ | $21$ | $8$ | $3$ |
Find the mean weight of the wrestlers (in $kg$).
Medium
View SolutionCalculate the mean of the following frequency distribution:
Class $10-20$ $20-30$ $30-40$ $40-50$ $50-60$ Frequency $12$ $16$ $8$ $6$ $8$
| Class | $10-20$ | $20-30$ | $30-40$ | $40-50$ | $50-60$ |
| Frequency | $12$ | $16$ | $8$ | $6$ | $8$ |
Medium
View SolutionThe mode of the following data is $33 \frac{1}{3}$ and the total frequency is $100$. Find the missing frequencies $x$ and $y$.
Class $0-10$ $10-20$ $20-30$ $30-40$ $40-50$ $50-60$ Frequency $7$ $12$ $x$ $28$ $y$ $9$
| Class | $0-10$ | $10-20$ | $20-30$ | $30-40$ | $40-50$ | $50-60$ |
| Frequency | $7$ | $12$ | $x$ | $28$ | $y$ | $9$ |
Medium
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