The mechanism of the reaction 2NO_2 + F_2 to | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The rate-determining step is the slow step,which is $(i)$ $NO_2 	o NO + O$.The rate law is determined by this slow step: $Rate = k[NO_2]^1$.Since

Vedclass · Accepted Answer

The reaction is zero order with respect to $F_2$.

Vedclass · Answer

(C) The rate-determining step is the slow step,which is $(i)$ $NO_2 	o NO + O$.The rate law is determined by this slow step: $Rate = k[NO_2]^1$.Since the rate depends only on the concentration of $NO_2$,the order of the reaction is $1$.For a first-order reaction,the half-life is given by $t_{1/2} = \frac{0.693}{k}$,which is independent of the initial concentration of the reactant.Therefore,the reaction is zero order with respect to $F_2$ because the rate expression does not contain $[F_2]$.

The mechanism of the reaction $2NO_2 + F_2 \to 2NO_2F$ is given by:
$(i)$ $NO_2 \xrightarrow{slow} NO + O$
$(ii)$ $F_2 + O + NO \xrightarrow{fast} NO_2F + F$
$(iii)$ $F + NO_2 \xrightarrow{fast} NO_2F$
Select the correct statement.

Similar Questions

For the chemical reaction $2A + 2B + C \rightarrow \text{Product}$,the rate law is given by $r \propto [A] [B]^2$. What is the order of the reaction?

The alkaline hydrolysis of an ester is a ........ reaction.

Write the unit of the rate constant for the following reactions:
$1.$ $5/2$ order
$2.$ $n$ order

When the temperature increases from $300 \, K$ to $310 \, K$,the rate of reaction increases by $2.3$ times. If the rate constant at $300 \, K$ is $x$,then the rate constant at $310 \, K$ will be equal to .......

Which of the following reactions is a termolecular reaction?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

The mechanism of the reaction $2NO_2 + F_2 \to 2NO_2F$ is given by:$(i)$ $NO_2 \xrightarrow{slow} NO + O$$(ii)$ $F_2 + O + NO \xrightarrow{fast} NO_2F + F$$(iii)$ $F + NO_2 \xrightarrow{fast} NO_2F$Select the correct statement.