The mean electrical energy density between th | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) For a parallel plate capacitor,the energy density $u = \frac{1}{2} \varepsilon_0 E^2$. Since the electric field $E$ between the plates is given by

Vedclass · Accepted Answer

$\frac{q^2}{2 \varepsilon_0 A^2}$

Vedclass · Answer

(A) For a parallel plate capacitor,the energy density $u = \frac{1}{2} \varepsilon_0 E^2$. Since the electric field $E$ between the plates is given by $E = \frac{\sigma}{\varepsilon_0}$,where $\sigma = \frac{q}{A}$ is the surface charge density. Substituting the value of $E$ in the energy density formula: $u = \frac{1}{2} \varepsilon_0 \left( \frac{\sigma}{\varepsilon_0} \right)^2 = \frac{\sigma^2}{2 \varepsilon_0}$. Now,substituting $\sigma = \frac{q}{A}$: $u = \frac{(q/A)^2}{2 \varepsilon_0} = \frac{q^2}{2 \varepsilon_0 A^2}$.

The mean electrical energy density between the plates of a charged air capacitor is (where $q=$ charge on capacitor,$A=$ area of capacitor plate):

Similar Questions

$A$ $12 \;pF$ capacitor is connected to a $50 \;V$ battery. How much electrostatic energy is stored in the capacitor?

$A$ parallel plate capacitor of capacitance $1 \ \mu F$ is charged to a potential difference of $20 \ V$. The distance between the plates is $1 \ \mu m$. The energy density between the plates of the capacitor is:

If $C$ is the capacitance and $V$ is the electric potential,then the dimensional formula of $C V^{2}$ is

The energy of a charged capacitor resides in

If the charge on the capacitor is increased by $3 \ C$,the energy stored in it increases by $44 \%$. The original charge on the capacitor is (in $C$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module