The mean deviation from the median for the fo | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) First,arrange the data in ascending order of $x_i$ and calculate the cumulative frequency:$x_i$$f_i$Cumulative Frequency$|x_i - M|$$f_i |x_i - M|$

Vedclass · Accepted Answer

$4.97$

Vedclass · Answer

(C) First,arrange the data in ascending order of $x_i$ and calculate the cumulative frequency:$x_i$$f_i$Cumulative Frequency$|x_i - M|$$f_i |x_i - M|$$3$$3$$3$$10$$30$$6$$4$$7$$7$$28$$9$$5$$12$$4$$20$$12$$2$$14$$1$$2$$13$$4$$18$$0$$0$$15$$5$$23$$2$$10$$21$$4$$27$$8$$32$$22$$3$$30$$9$$27$Here,$N = \Sigma f_i = 30$.The median is the value corresponding to the cumulative frequency just greater than $\frac{N}{2} = 15$.The cumulative frequency $18$ corresponds to $x_i = 13$. Thus,Median $(M) = 13$.The sum $\Sigma f_i |x_i - 13| = 30 + 28 + 20 + 2 + 0 + 10 + 32 + 27 = 149$.Mean deviation from median $= \frac{\Sigma f_i |x_i - M|}{N} = \frac{149}{30} \approx 4.97$.

The mean deviation from the median for the following distribution (corrected to $2$ decimals) is
$x_i$ $3$ $6$ $9$ $12$ $13$ $15$ $21$ $22$
$f_i$ $3$ $4$ $5$ $2$ $4$ $5$ $4$ $3$

Similar Questions

Find the mean deviation about the mean for the following data:
$6, 7, 10, 12, 13, 4, 8, 12$

What is the mean deviation about the mean of the series $a, a + d, a + 2d, \dots, a + 2nd$?

What is the coefficient of mean deviation about the median for the observations $40, 62, 54, 90, 68, 76$?

The mean deviation about the mean for the observations $ -1, 0, 4 $ is:

For a frequency distribution,the mean deviation from the mean is computed by:

Vedclass Test Series

Exam Paper Generator

Online Exam Module

$x_i$	$3$	$6$	$9$	$12$	$13$	$15$	$21$	$22$
$f_i$	$3$	$4$	$5$	$2$	$4$	$5$	$4$	$3$

The mean deviation from the median for the following distribution (corrected to $2$ decimals) is$x_i$$3$$6$$9$$12$$13$$15$$21$$22$$f_i$$3$$4$$5$$2$$4$$5$$4$$3$