The maximum power delivered to resistance R i | vedclass

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Question

$P_{\max }=\frac{V_{a b}^{2}}{4 R_{a b}} ; P_{\max }=\frac{16}{4 	imes 10}=0.4 \mathrm{\,watt}$

$\mathrm{V}_{\mathrm{ab}}=\frac{12}{9} 	imes 3=4

Vedclass · Accepted Answer

$0.4$

Vedclass · Answer

$P_{\max }=\frac{V_{a b}^{2}}{4 R_{a b}} ; P_{\max }=\frac{16}{4 	imes 10}=0.4 \mathrm{\,watt}$

$\mathrm{V}_{\mathrm{ab}}=\frac{12}{9} 	imes 3=4 \mathrm{\,volt}$

$\mathrm{R}_{\mathrm{ab}}=8+\frac{6 	imes 3}{9}=8+2=10\, \Omega$

The maximum power delivered to resistance $R$ is ............... $W$

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