In the circuit shown here,the readings of the | vedclass

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(C) The circuit consists of a battery with $EMF$ $E = 6\, V$ and internal resistance $r = 1\, \Omega$. The external circuit consists of two resistors

Vedclass · Accepted Answer

$6/11\, A, 60/11\, V$

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(C) The circuit consists of a battery with $EMF$ $E = 6\, V$ and internal resistance $r = 1\, \Omega$. The external circuit consists of two resistors of $6\, \Omega$ and $4\, \Omega$ connected in series.The total resistance of the circuit is $R_{total} = R_1 + R_2 + r = 6\, \Omega + 4\, \Omega + 1\, \Omega = 11\, \Omega$.The current $i$ flowing through the circuit is given by Ohm's law: $i = \frac{E}{R_{total}} = \frac{6\, V}{11\, \Omega} = \frac{6}{11}\, A$.The voltmeter is connected across the external circuit (the series combination of $6\, \Omega$ and $4\, \Omega$ resistors). The potential difference $V$ across these resistors is $V = i 	imes (R_1 + R_2) = \frac{6}{11}\, A 	imes (6\, \Omega + 4\, \Omega) = \frac{6}{11} 	imes 10 = \frac{60}{11}\, V$.Thus,the ammeter reading is $6/11\, A$ and the voltmeter reading is $60/11\, V$.

In the circuit shown here,the readings of the ammeter and voltmeter are

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