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Question

(A) The molecule $1-$bromo$-2-$methylcyclobutane contains two chiral centers at $C1$ and $C2$. Since the ring is not symmetric,the number of stereoiso

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$4$

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(A) The molecule $1-$bromo$-2-$methylcyclobutane contains two chiral centers at $C1$ and $C2$. Since the ring is not symmetric,the number of stereoisomers is given by $2^n$,where $n$ is the number of chiral centers. Here,$n = 2$,so the total number of stereoisomers is $2^2 = 4$. These $4$ stereoisomers consist of two pairs of enantiomers (cis-isomer pair and trans-isomer pair),all of which are optically active. Therefore,the maximum number of possible optical isomers is $4$.

The maximum number of possible optical isomers in $1-$bromo$-2-$methylcyclobutane is

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