The number of optical isomers of an organic compound having $n$ asymmetric carbon atoms will be
- A$2^{n + 1}$
- B$n^2$
- C$2^n$
- D$2^{n - 1}$
Explore More
Similar Questions
Which of the following compounds will exhibit optical isomerism?
Difficult
View SolutionThe maximum number of possible optical isomers in $1-$bromo$-2-$methylcyclobutane is
DifficultKCET 2011
View SolutionThe structure of $(S)-2$-fluorobutane is best represented by:
Difficult
View SolutionAmong the structures given, select the enantiomers.
Medium
View SolutionWhich of the following molecules contains stereogenic $C-$ atoms?
Difficult
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo