(C) According to Wien's displacement law,$\lambda_{m} T = b$,where $b$ is Wien's constant.Therefore,$\lambda_{1} T_{1} = \lambda_{2} T_{2}$.Given $\la

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(C) According to Wien's displacement law,$\lambda_{m} T = b$,where $b$ is Wien's constant.Therefore,$\lambda_{1} T_{1} = \lambda_{2} T_{2}$.Given $\lambda_{1} = 11 \times 10^{-5} \text{ cm}$ and $\lambda_{2} = 5.5 \times 10^{-5} \text{ cm}$.We are given $T_{1} = n T_{2}$.Substituting these values into the equation: $(11 \times 10^{-5}) \times (n T_{2}) = (5.5 \times 10^{-5}) \times T_{2}$.Dividing both sides by $T_{2}$ and $10^{-5}$,we get $11n = 5.5$.Thus,$n = \frac{5.5}{11} = 0.5$.

Class 11 Chemistry Data Entry - Chemistry Level 0 of all question bank

The maximum energy in the thermal radiation from a hot source occurs at a wavelength of $11 \times 10^{-5} \text{ cm}$. According to Wien's law,the temperature of the source (on Kelvin scale) will be $n$ times the temperature of another source (on Kelvin scale) for which the wavelength at maximum energy is $5.5 \times 10^{-5} \text{ cm}$. The value of $n$ is

A
$2$
B
$4$
C
$0.5$
D
$1$

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